Tugas Jaringan Komputer (26 Maret 2013)
CCNA Exploration 4.0 Networks Fundamental
Activity 6.7.3: IPv4
Address Subnetting Part 1
Learning Objectives
Upon
completion of this activity, you will be able to determine network information
for a given IP address and network mask.
Background
This
activity is designed to teach how to compute network IP address information
from a given IP
address.
Scenario
When given an IP address and
network mask, you willbe able to determine other information about the
IP address such as:
•Network address
•Network broadcast address
•Total number of host bits
•Number of hosts
Task 1: For a given IP address, Determine
Network Information.
Given:
Host IP Address 172.25.114.250
Network Mask 255.255.0.0 (/16)
Find:
Network
Address, Network Broadcast, Address
total Number of Host Bits, Number of Hosts
Step 1: Translate Host IP address and
network mask into binary notation.
Convert the
host IP address and network mask to binary:
172 25 114 250
IP Address 10101100 11001000 01110010 11111010
Network Mask 11111111 11111111 00000000 00000000
255 255 0 0
Step 2: Determine the network address.
1. Draw a
line under the mask.
2. Perform a
bit-wise AND operation on the IP address and the subnet mask.
Note:1 AND 1
results in a 1; 0 AND anything results in a 0.
3. Express
the result in dotted decimal notation.
4. The result is the network address for this host IP
address, which is 172.25.0.0.
IP Address 10101100 11001000 01110010 11111010 (172.25.114.250)
Subnet Mask 11111111 11111111 00000000 00000000 (255.255.0.0)
Network Address 10101100 11001000 00000000 00000000 ( 172.25.0.0)
Step 3: Determine the broadcast address
for the network address
The network
mask separates the network portion of the address from the host portion. The
network
address has
all 0s in the host portion of the address and the broadcast address has all 1s
in the host
portion of
the address.
172 25 0 0
Network
Add. 10101100 11001000
00000000 00000000
Mask 11111111 11111111
00000000 00000000
Broadcast. 10101100 11001000
11111111 11111111
172 25 255 255
By counting the number of host bits, we can determine the total number
of usable hosts for this network.
Host bits: 16
Total number of hosts:
2^16 =
65,536
65,536 – 2 =
65,534 (addresses that cannot use the all 0saddress, network address, or the
all 1s
address, broadcast address.)
Add this
information :
- Host IP Address = 172.25.114.250
- Network Mask = 255.255.0.0 (/16)
- Network Address = 172.25.0.0
- Network Broadcast Address = 172.25.255.255
- Total Number of Host Bits = Host bits 16 and total number of host 65.534
Task 2: Challenge
For all
problems:
Create a
Subnetting Worksheet to show and record all work for each problem.
Problem 1
Host IP Address 172.30.1.33
Network Mask 255.255.0.0 (/16)
Network
Address (?) = 172.30.1.0
Network
Broadcast Address (?) = 172.30.255.255
Total Number
of Host Bits (?) and Number of
Hosts (?) = Host bits 16 and total number of host 65.534
Problem 2
Host IP Address 172.30.1.33
Network Mask 255.255.255.0 (/24)
Network
Address (?) = 172.30.1.0
Network
Broadcast Address (?) = 172.30.1.255
Total Number
of Host Bits (?) = 8
Number of
Hosts (?) : 2^8 - 2 = 256 - 2 = 254 hosts
Problem 3
Host IP Address 192.168.10.234
Network Mask 255.255.255.0 (/24)
Network
Address (?) = 192.168.10.0
Network
Broadcast Address (?) = 192.168.1.255
Total Number
of Host Bits (?) = 8
Number of
Hosts (?) = 2^8 -2 = 256 - 2 = 254 hosts
Problem 4
Host IP Address 172.17.99.71
Network Mask 255.255.0.0 (/16)
Network
Address (?) = 172.17.0.0
Network
Broadcast Address (?) = 172.17.255.255
Total Number
of Host Bits (?) = 16
Number of
Hosts (?) : 2^16-2 = 65,536 – 2 = 65,534 hosts
Problem 5
Host IP Address 192.168.3.219
Network Mask 255.255.0.0 (/16)
Network
Address (?) = 192.168.0.0
Network
Broadcast Address (?) = 192.168.255.255
Total Number
of Host Bits (?) = 16
Number of
Hosts (?): 2^16-2 = 65,536 – 2 = 65,534 hosts
Problem 6
Host IP Address 192.168.3.219
Network Mask 255.255.255.224
Network
Address (?) = 192.168.3.192
Network
Broadcast Address (?) = 192.168.3.223
Total Number
of Host Bits (?) = 5
Number of
Hosts (?): 2^5-2 = 32 -2 = 30 hosts
Task 3: Clean Up
Remove
anything that was brought into the lab, and leave the room ready for the next
class.
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